Math, asked by karencorreya8b, 17 days ago

(i) no defective books ?
(ii) more than 0 but less than 4 defective books ?
(iii) more than 4 defective books ?

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Answered by gayatridevi638658542

0

Answer:

(I) 400

(2)669. no of books =400+180+48+41

(3)31. no of books = 18+8+2+3

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