Question

i only need ans of b,c and d​

Answer 1

Answer:

Don't know the answer bro

Answer 2

EVALUTION★≈

$(b) \: \:( (\frac{ - 2}{ \: \: \: 3}) {}^{3} ) {}^{2}$

• we know that

• when power is above the pawer then
• powers are multiplied by-----(2
• it means
• $(a {}^{m} ) {}^{n} = a {}^{m \times n}$

• even power value always pogitive

$= > a {}^{2m} = + n$

$= ( \frac{ - 2}{ \: \: \: 3} ) {}^{3 \times 2} \\ \\ = ( \frac{ - 2}{ \: \: \: 3} ) {}^{6} \\ \\ = \frac{64}{729}$

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• similarly eq 2 rule

• $(c) \: \:(( ( \frac{ - 1}{ \: \: \: 2} ) {}^{2} ) {}^{2} ) {}^{ - 1} \\ \\ = (( \frac{ - 1}{ \: \: \: 2} ) {}^{2 \times 2} ) {}^{ - 1} \\ \\ = ( \frac{ - 1}{2} ) {}^{4 \times - 1} \\ \\ = ( \frac{ - 1}{2} ) {}^{ - 4}$
• we know that
• when any power move
• denomiter to numerator and numerator to denomiter power
• value change pogitive to
• negative or negative to pogitive

• it means

• $a {}^{ - m} = \frac{1}{a {}^{m} }$

• $= ( \frac{ - 2}{1} ) {}^{4} \\ \\ = (- 2) {}^{4} \\ \\ = 16$
• $</li><li>(d) \: \: ((\frac{5}{4} ) {}^{2} ) {}^{2} \\ \\ = (\frac{5}{4}) {}^{2 \times 2} \\ \\ = (\frac{5}{4} ) {}^{4} \\ \\ = \frac{625}{256}$

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answer★

• (b) =64/729

• (c) =16

• (d) =625/256

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i hope it helps you ✅