Question

I only want answer of the 2nd question from this pic
In the figure ∠AED = ∠ABC
AD=3, BD=5, AE=4
Find AC
Please answer fast!!!

Answer 1

In the figure ∠ADE = ∠ABC AD=3, BD=5, AB=4 Find AC

question should be this

Step-by-step explanation:

from fig

∠ADE = ∠ABC so,BC||DE( Bcz BD is acting like Transversal and ∠ADE = ∠ABC )

from B.PT

△ADE∼△ABC

$\frac{AD}{AB} = \frac{AE}{AC} \\ \frac{3}{8} = \frac{4}{x} \\ 3x = 8 \times 4 \\ x = \frac{32}{3}$

therefore AC=32/3

Answer 2

Answer:

Answer

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Ssrinivas

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In the figure ∠ADE = ∠ABC AD=3, BD=5, AB=4 Find AC

question should be this

Step-by-step explanation:

from fig

∠ADE = ∠ABC so,BC||DE( Bcz BD is acting like Transversal and ∠ADE = ∠ABC )

from B.PT

△ADE∼△ABC

therefore AC=32/3

Step-by-step explanation: