Math, asked by mohitsigroha807415, 2 months ago

I p is not a multiple of n then sum of pth power of nth roots of unity is ​

Answers

Answered by gouravgupta65
1

Answer:

nth roots of unity are 1,a,a

2

,...,a

n−1

where a=cos(

n

)+isin(

n

)

Therefore the sum of the pth power of these roots =1

p

+a

p

+a

2p

+a

3p

+...a

(n−1)p

...(1)

Case 1) If p is not a multiple of n, we have

a

p

=[cos(

n

)+isin(

n

)]

p

=cos[2π(

n

p

)]+isin[2π(

n

p

)]

=1

Because (

n

p

) is not an integer. So in this case summing the G.P in (1) whose common ratio a

p

in not 1, we have

the sum of the pth powers of the roots

=

1−a

p

1−(a

p

)

n

=

1−a

p

1−a

pn

=

1−a

p

1−(a

n

)

p

=

1−a

p

1−1

Since a

n

=1,a being nth root of unity

=

1−a

p

0

=0,a

p

=1

Case 2) If p is a multiple of n, say p=mn, where m is integer, then a

p

=a

mn

=(a

n

)

m

=1

m

=1

So in this case each term in (1) is equal to 1 and the sum of the pth powers of the roots

=1+1+1+...1 (upto n terms ) =n

Answered by Anonymous
4

Answer:

hope it will be helpful to you dear friend

1st pic and pic is same

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