Question

i P(x) = x^3+ x²- 9 x - 9
P(0)​

Answer 1

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p(x) = p(0)

So, it means put 0 in the place of x in this equation...

$x {}^{3} + x {}^{2} - 9x - 9 \\ (0) {}^{3} + (0) {}^{2} - 9(0) - 9 \\ 0 + 0 - 0 - 9 \\ = - 9$

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hope it helps