i pavoue !yang that (cosnt cosyl ² + (sin na siny) - 4 cas? ਕ
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Answer:
LHS=cos
2
A+cos
2
B+2cosAcosB+sin
2
A+sin
2
B−2sinAsinB
(cos
2
A+sin
2
A)+(cos
2
B+sin
2
B)+2cosAcosB−2sinAsinB
2+2cosAcosB−2sinAsinB
2+cos(A+B)+cos(A−B)−cos(A−B)+cos(A+B)
2+2cos(A+B) (∴cosx=2cos
2
2
x
−1)
2+2[2cos
2
2
(A+B)
−1]
2+4cos
2
2
(A+B)
−2=4cos
2
2
(A+B)
=R.H.S
Hence proved.
Step-by-step explanation:
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