(i) Pb → Pb2+ + 2e-
(iii) A3+ + e-1 → A2+
(ii) Fe2+
e- → Fe3+
(iv) Cu → Cu2+,state which are reduction reaction and oxidation
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(i) Its oxidation reaction since lead loses 2 electrons to form Pb2+.
(ii) Its reduction reaction since A3+ ion gains on electron to form A2+ ion.
(iii) Its oxidation reaction since ferrous ion loses one electron to form ferric ion.
( the electron must be on the right side of the arrow)
(iv) Its oxidation reaction since copper loses 2 electrons to form cuprous ion.
Hope this answer helps you.
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