i)Plot the following points on the coordinate plane . A (-4,4), B ( -6,0) ,C ( -4,-4),D( -2,0).
ii)Name the figure formed by joining the points A,B,C,D and also find its area.
Answers
Answer:
Figure we obtained is Rhombus and Area is 16 unit².
Step-by-step explanation:
Given:
Coordinates of the points,
A( -4 , 4 ) , B( - 6 , 0 ) , C( -4 , -4 ) and D( -2 , 0 )
We need to plot the points in the coordinate plane and name the figure. Find the Area of the Figure.
Graph is attached after plotting.
ABCD is a Rhombus as opposite sides are parallel and all sides are equal and Diagonals are perpendicular bisector of each other.
Area of the Rhombus ABCD = Area of the ΔABD + Area of the ΔACD
From the figure,
In ΔABD
Base = 4 unit
Height = 4 unit
In ΔACD
Base = 4 unit
Height = 4 unit
Area of the Rhombus ABCD = 1/2 × Base × Height + 1/2 × Base × Height
= 1/2 × 4 × 4 + 1/2 × 4 × 4
= 8 + 8
= 16 unit²
Therefore, Figure we obtained is Rhombus and Area is 16 unit².
Answer:
Step-by-step explanation:
Rhombus is the figure and the area is 16 unit.
Hope it helps you.
