(-i)⅓=?
plz solve this
Answers
Answered by
1
Answer:
Let x
3
=−i
or
⇒(x
3
+i)=0
⇒(x
3
+(−i)
3
)=0
⇒(x
3
−(i)
3
)=0
⇒(x−i)(x
2
−1+ix)=0
∴x=i
and
⇒x
2
+ix−1=0
⇒x=
2
−i±
−1+4
=
2
−i±
3
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