i power30 + i power 40+ i power 60
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Answered by
1
Answer:
3
Step-by-step explanation:
i=-1
i^30+i^40+i^60
(-1)^30+(-1)^40+(-1)^60
1+1+1
=3
Answered by
28
Question →
i^30 + i^40 + i^60 .
Solution →
i^30 , i^40 and i^60 can be written in another way .
Here writing power of iota as the Multiple of 4 .
{i^(4×7)× i^2 } + { i^(4×19)} + {i^(4×15)}
✍️ As we know that i⁴ = 1 and also multiple of i⁴ is equal to 1 . So,
1 × i² + 1 + 1
i² + 2
✍️ And i² = -1
-1 +2
1
So, i^30 + i^40 + i^60 = 1 .
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