Question

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Answer 1

Correct Questions:

1. Find the value of
2. ${64}^{ \frac{2}{3} }$
3. Find the Value of 2x³ - 3x + √5 when x = (-3)

Process:

1.

${64}^{\frac{2}{3} } \\ = {4}^{3 \times \frac{2}{3} } \\ = {4}^{2} \\ = 16$

Therefore,

${64}^{ \frac{2}{3} } = 16$

2. We have to find value of this polynomial where x = (-3)

p(x) = 2x³ - 3x + √5

x = (-3)

So, p(-3) = 2(-3)³ - 3(-3) + √5

= 2 (-27) + 9 + √5

= (-54) + 9 + √5

= (-45) + √5

$( - 45) + \sqrt{5}$

Therefore,

$p(x) = 2x³ - 3x + √5 \\ \: \: \: where \: \: \: </p><p> x = (-3)$

Answer:

1. 16

2. (-45) + √5