Math, asked by dalelamamta2406, 10 months ago

i) Prove that
Cos (45° -A) Cos (45° - B) - Sin (45° - A) Sin (45° - B) = Sin (A + B)​

Answers

Answered by fathimaroohee
1

Answer:

hope it helps you

please mark as brainliest answer

Attachments:
Answered by rk7048942344
2

Answer:

(sorry for late my internet was slow)

Step-by-step explanation:

Cos(45-A+45-B). :: cos(A+B)

cos(90-(A+B))

cos(90)cos(A+B)+sin(90)sin(A+B). :: cos(A-B)

0+sin(A+B). :: cos(90)=0,sin(90)=1

sin(A+B)

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