Math, asked by ganu47, 4 months ago

(i) Quadrilateral JUMP
JU = 3.5 cm
UM=4 cm
MP= 5 cm
PJ=4.5 cm
PU= 6.5 cm​

Answers

Answered by IAmAjAnkit
0

Answer:

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Step-by-step explanation:

Steps of Construction :

Draw JU = 3.5 cm.

With J as centre and radius JP = 4.5 cm, draw an arc.

With U as centre and radius UP = 6.5 cm, draw another arc to intersect the arc of step 2 at P.

With U as centre and radius UM = 4 cm, draw an arc on the side of PU opposite to that of J.

With P as centre and radius PM = 4 cm, draw another arc to intersect the arc of step 4 at M.

Join UM, MP, PJ and UP.

Then, JUMP is the required quadrilateral.

Answered by Anonymous
8

Given;

JU = 3.5 cm,UM 4cm,MP = 5cm,PJ = 4.5 cm PU= 6.5cm

To construct :- A quadrilateral JUMP

Steps of constuction:

a Draw JU = 3.5 cm.

b) Draw an arc of radius 4.5cm taking centre J and then draw another arc of radius 6.5cm taking U as centre. Both arcs intersect at P.

c) Join PJ and PU.

d) draw arc of radius 5cm and 4cm taking P and U as centres respectively, which intersect at M. Join MP and mu.

It is required quadrilateral JUMP.

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