Question

I,R,+I,R,
1,R, -1,R₂
(3) 11
(4) L-1
The potential difference between A and B in the
following figure is :-
4V
AWB
2A 12V 902 592
(1) 24 V (2) 14 V (3) 32 V (4) 48 V
692

HELP ME OUT.​

Answer 1

Answer :

A

Solution :

Resistance of the upper arm

<br> Resistance of the lower arm

<br> As the resistance of both arm are equal, therefore same amount of current flows in both the arms. Current through each arm. CAD or CBD=1A <br> Potential difference across C and A is

<br> Potential difference across C and B is

<br> Substracting (i) from (ii), we get <br>

Answer 2

Aɴꜱᴡᴇʀ

$\sf{} \green{potential \: difference= 20 \: v}$

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Gɪᴠᴇɴ

There are 3 resistors of 6 Ohm ,9 Ohm and 5 Ohm connected in series

I = 2 A

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ᴛᴏ ꜰɪɴᴅ

Potential difference?

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Sᴛᴇᴘꜱ

$\tt{}the \: total \: resistance \: = r1 + r2 + r3 \\ \\ \tt{} \leadsto6 +9 + 5 \\ \\ \dashrightarrow{} \tt \pink{20 \: ohm}$

So now according to the Ohm's law voltage is given by,

$\huge \orange{\boxed{ \tt{}v = ir}}$

• Where V= voltage
• I= Current
• And R denotes resistance

$\bigstar$Calculation

$\large \tt{}v = 2 \times 20 \\ \\ \large \pink{ \tt\dashrightarrow{}v =20 \: vol ts}$

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$\huge{\mathfrak{\purple{hope\; it \;helps}}}$