i) /R-R defined by f(x)=x+5
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f(x)=x 5
y=f(x)=x 5
x=f −1= 5y
Because f −1
is defined for all y∈R, we have that f is surjective or onto.
The implication y 1 =y 2
⇒f −1(y 1 )=f −1 (y 2)
entails that f is injective or one-one.
Being surjective and injective it is bijective (one-to-one).
Step-by-step explanation:
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