Question

i)r(t)=4t²+3t³-t²+6 at t=p,tER ii) s(z)=z³-1 at z=1 iii) p(x)=3x²+5x-7 at x=1 iv)q(z)=5z³-4z+root 2 at z=2​

Answer 1

Answer:

We substitute the variable t=p the given polynomial r(t)=4t

4

+3t

3

−t

2

+6 as follows:

r(p)=4p

4

+3p

3

−p

2

+6

Hence, the value of the given polynomial with t=p is r(p)=4p

4

+3p

3

−p

2

+6.