I
Rationalise
the
denominator and
simplify.
√2+1÷√2-1
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√2+1/√2-1
(Rationalise)
=> √2+1/√2-1 × √2+1/√2+1
[(a+b)×(a-b) = a square - b square]
Therefore, (√2+1) square/ (√2) square - (1) square
=> (√2+1) square/ 2-1
=> (√2+1) square/ 1
=> (√2+1) square
[(a+b) square = (a) square + (b) square + 2×a×b]
(√2) square + (1) square + 2×√2×1
=> 2 + 1 + 2√2
=> 3+ 2√2
Therefore, ans= 3+2√2
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