Question

i) Rationalize the denominator
7+ √3 very fast

Answer 1

Correct Question:

Rationalize the denominator:-

1/7+√3

Answer:-

$\bf \implies \frac{1}{7 + \sqrt{3} }$

$\: \bf \implies \frac{1}{7 + \sqrt{3} } \times \frac{7 - \sqrt{3} }{7 - \sqrt{3} }$

$\bf \implies \frac{7 - \sqrt{3} }{ {(7)}^{2} - {( \sqrt{3}) }^{2} }$

$\bf \implies \frac{7 - \sqrt{3} }{49 - 3}$

$\bf \implies \frac{7 - \sqrt{3} }{46}$

$\bf \huge \fbox \red{ \: answer : \: \frac{7 - \sqrt{3} }{46} \: }$

Answer 2

Answer:

Correct Question:

Rationalize the denominator:-

1/7+√3

Answer:-

\bf \implies \frac{1}{7 + \sqrt{3} }⟹7+31

\: \bf \implies \frac{1}{7 + \sqrt{3} } \times \frac{7 - \sqrt{3} }{7 - \sqrt{3} }⟹7+31×7−37−3

\bf \implies \frac{7 - \sqrt{3} }{ {(7)}^{2} - {( \sqrt{3}) }^{2} }⟹(7)2−(3)27−3

\bf \implies \frac{7 - \sqrt{3} }{49 - 3}⟹49−37−3

\bf \implies \frac{7 - \sqrt{3} }{46}⟹467−3