I read 3/8 of a book on one day, and 4/5 of the remainder on another day. if now there were 30 pages unread, the book contains:
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Answered by
13
Hey!
Let the book contains x pages.
In a day pages read= 3/8 of x.
= 3x/8.
Remaining pages= x-3x/8.
= (8x-3x)/8.
= 5x/8.
In another days pages read= 4/5 of 5x/8.
= 20x/40= x/2 .
Remaining pages= 5x/8 - x/2.
=( 5x-4x)/8.
= x/8.
Also Pages remaining= 30.
So x/8 = 30.
x= 30*8.
= 240 pages.
The book contains 240 pages.
Hope it helps.
Let the book contains x pages.
In a day pages read= 3/8 of x.
= 3x/8.
Remaining pages= x-3x/8.
= (8x-3x)/8.
= 5x/8.
In another days pages read= 4/5 of 5x/8.
= 20x/40= x/2 .
Remaining pages= 5x/8 - x/2.
=( 5x-4x)/8.
= x/8.
Also Pages remaining= 30.
So x/8 = 30.
x= 30*8.
= 240 pages.
The book contains 240 pages.
Hope it helps.
Answered by
4
Answer:
Let the total pages be 'x' in number.
According to condition 1:
3/8*x read on first day.
So remaining pages will be :
1-3/8*x
=5/8*x
According to condition 2:
Read 4/5 of remaining
So left unread =1/5 of remaining
Therefore remaining at last=1/5 * 5/8*x
=1/8x
Unread=30
Therefore:1/8*x = 30
>> X=240.
Therefore total page is 240
Step-by-step explanation:
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