I read 4/9 of a book on one day and 3/5 of the remaining on the other day. If 100 pages of the book are still left unread, find the number of pages.
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Hi there!
Number of pages read on 1st day = 4/9 of total
Number of pages read on 2nd day = 3/5 of the remaining
∴, 5/9 = 3/5 + 100
So,
⇒ 2/5 × 5/9 = 100
⇒ 2/9 = 100
⇒ 1/9 = 50
So,
Total pages =
⇒ 9/9 = 9×(1/9)
⇒9 × 50
⇒ 450
∴, there are 450 pages in the book.
To check:
⇒ 4/9×450 = 200
⇒ 5/9 = 250 (450-200)
⇒ 3/5 × 250 = 150
⇒ 2/5 = 100
⇒ 200 + 150 + 100
⇒ 450
Hope it helps you!!
Number of pages read on 1st day = 4/9 of total
Number of pages read on 2nd day = 3/5 of the remaining
∴, 5/9 = 3/5 + 100
So,
⇒ 2/5 × 5/9 = 100
⇒ 2/9 = 100
⇒ 1/9 = 50
So,
Total pages =
⇒ 9/9 = 9×(1/9)
⇒9 × 50
⇒ 450
∴, there are 450 pages in the book.
To check:
⇒ 4/9×450 = 200
⇒ 5/9 = 250 (450-200)
⇒ 3/5 × 250 = 150
⇒ 2/5 = 100
⇒ 200 + 150 + 100
⇒ 450
Hope it helps you!!
Anonymous:
check with the answers
is my answer correct?
Thanks. It's correct.
thanks!!
Could you explain me in
Sorry
Could you explain it to me in more detail especially in the part where you wrote 5/9=3/5+100
ok wait
Look, the whole book = 9/9
So he read 4/9, so remaining is 5/9
Next day he reads 3/5 of the 5/9
So 2/5 remaining = 100
So, 5/9 = 3/5 + 100 or not??
So he read 4/9, so remaining is 5/9
Next day he reads 3/5 of the 5/9
So 2/5 remaining = 100
So, 5/9 = 3/5 + 100 or not??
understood?
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