Question

I REALLY NEED HELP HERE ON THIS ONE

PLZ HELP ME OUT

BEST WILL BE BRAINLIEST

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THNX.

Answer 1

1. Substitute 2 for n.

LHS is
${1}^{2} + {2}^{2} = 5$
RHS is
$\frac{2 \times (2 + 1) \times (2 \times 2 + 1)}{6} = \frac{30}{6} \\ = 5$
Therefore, P(2) is true

2. Substitute 5 for n.

LHS is
${1}^{2} + {2}^{2} + {3}^{2} + {4}^{2} + {5}^{2} = 55$
RHS is
$\frac{5 \times (5 + 1) \times (2 \times 5 + 1)}{6} \\ = \frac{5 \times 6 \times 11}{6} = 5 \times 11 = 55$
Therefore, P(5) is true