Question

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Balance the following chemical equations :---- 5

a) NaOH (hot) + Cl2 NaCl + NaClO3 + H2O

b) Zn + HNO3 Zn(NO3)2 + N2O +H20

c) As + HNO3 H3AsO4 + NO2 + H2O

d) S + HNO3 H2SO4 + NO2 + H2O

e) K2Cr2O7 + H2SO4 + SO2 K2SO4 + Cr2(SO4)3 + H2O​

Answer 1

Explanation:

a 6NaOH + 3Cl2 → 5NaCl + NaClO3 + 3H2O

b 4Zn + 10HNO3 → 4Zn(NO3)2 + N2O + 5H2O

c As + 5HNO3 → H3AsO4 + 5NO2 + H2O

d S (s) + 6 HNO3 (aq) → H2SO4 (aq) + 6 NO2 (l) + 2 H2O (l)

This is an oxidation-reduction (redox) reaction:

S0 - 6 e- → SVI

(oxidation)

6 NV + 6 e- → 6 NIV

(reduction)

S is a reducing agent, HNO3 is an oxidizing agent.

e K2Cr2O7 + H2SO4 + 3SO2 → K2SO4 + Cr2(SO4)3 + H2O

Answer 2

Answer:

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Explanation:

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