Question

I recievd two salary hikes during the current financial year. The first time, my salary was hiked by x% while the second time it was hiked by 2x% .my current salary is 1.875times of my salary at the starting of the year .find the value of x

Answer 1

Answer:

The value of x is 25

Explanation:

Let my salary was P

After first hike of x% the salry will be P + Px/100 = P(1 + x/100)

After the second hike of 2x% the salary will be

= P(1 + x/100) + P(1 + x/100)× 2x/100

= P[1 + x/100 + 2x/100 + 2x²/10000]

According to the question

P[1 + x/100 + 2x/100 + 2x²/10000] = 1.875P

$\implies  1+\frac{3x}{100} +\frac{2x^2}{10000}=1.875$

$\implies  10000+300x +2x^2=18750$

$\implies  2x^2+300x-8750=0$

$\implies  x^2+150x-4375=0$

$\implies  x^2+175x-25x-4375=0$

$\implies  x(x+175)-25(x+175)=0$

$\implies  (x+175)(x-25)=0$

$\implies  x=25, -175$

But x cannot be negative

Thus x = 25

Therefore the hike in the salary is 25%