Question

I request u to write in a paper and send please ....
factorise 8a³ - b³ - 12a²b + 6ab²

Answer 1

8a³ – b³ – 12a²b + 6ab²


By identity [(a + b)³ = a³ + b³ + 2a²b + 2ab²]


= (2a)³ + (-b)³ + 3 x (2a)² x (-b) + 3 x 2a x (-b)²
= (2a - b)³

Answer 2

Given Equation is 8a^3 - b^3 - 12a^2b + 6ab^2

= > (2a)^3 - (b)^3 - 6ab(2a - b)

= > (2a)^3 - (b)^3 - (3)(2a)(b)(2a - b)

It is in the form of a^3 - b^3 - 3ab(a - b) = (a - b)^3

Here, a = 2a, b = 3.

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Therefore, the result is (2a - b)^3

Hope this helps!