Question

I require an answer as soon as plausible.
The radii of the ends of a frustum of a cone 40cm high are 38 cm and 8 cm. Find the slant height of the frustum.​

Answer 1

50 cm

in order to see the step-by-step solution

please see in attachment .

plz..mark me

Answer 2

Answer:

Slant height of the frustrum is 50cm.

Step-by-step explanation:

Given:

height of cone = $h=40cm$

radii of cone =>

$R_{1} = 38cm\\R_{2} = 8cm$

Slant height = $l = \sqrt{h^{2}+(R_{1} -R_{2} )^{2} }$

Putting the values,

$l = \sqrt{(40)^{2}+(38 -8 )^{2} }$

$l = \sqrt{1600+900 } = \sqrt{2500}$

$l=50$