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Aluminum is in group IIIA of the periodic table therefore it has three valence electrons. The symbol for aluminum is Al which will be surrounded by three dots. 2. Give the electron dot structure of chlorine.
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1. By Angle Angle axiom (AA axiom)
2. CP / CQ = PA / QB = CA / CB
3. AC = 10.5cm
Step-by-step explanation:
1. In ΔCPA and ΔCQB
∠CPA = ∠CQB (Given)
∠QCB = ∠PCA (Given)
Hence proved.
3. BQ / BC = AP / AC
8 / 12 = 7 / AC ⇒ AC = (7 × 3) / 2
AC = 21 / 2 ⇒ AC = 10.5
Hope this answer helps you.
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