Math, asked by keshab111, 7 months ago

(i) sec

2 θ + cosec2 θ = sec

2 θ × cosec

2 θ​

Answers

Answered by div2007
1

Answer:

sec  

2

θ+cosec  

2

θ=  

cos  

2

θ

1

​  

+  

sin  

2

θ

1

​  

 

                          =  

sin  

2

θcos  

2

θ

sin  

2

θ+cos  

2

θ

​  

 

                          =  

sin  

2

θcos  

2

θ

1

​  

 

                          =sec  

2

θ×cosec  

2

θ

Step-by-step explanation:

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