Math, asked by keshab111, 6 months ago

(i) sec

2 θ + cosec2 θ = sec

2 θ × cosec

2 θ

Answers

Answered by div2007

1

Answer:

sec

2

θ+cosec

2

θ=

cos

2

θ

1

+

sin

2

θ

1

=

sin

2

θcos

2

θ

sin

2

θ+cos

2

θ

=

sin

2

θcos

2

θ

1

=sec

2

θ×cosec

2

θ

Step-by-step explanation:

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