(i) sec
2 θ + cosec2 θ = sec
2 θ × cosec
2 θ
Answers
Answered by
1
Answer:
sec
2
θ+cosec
2
θ=
cos
2
θ
1
+
sin
2
θ
1
=
sin
2
θcos
2
θ
sin
2
θ+cos
2
θ
=
sin
2
θcos
2
θ
1
=sec
2
θ×cosec
2
θ
Step-by-step explanation:
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