Question

(i) sec (90° + A) + x sin A tan (90° + A) = cos (90° + A).​

Answer 1

Answer:

Step-by-step explanation:

sec(90+A)+x sin A tan(90+A)=cos(90+A)

-cosec A +x sinA(-cot A)=-sin A

x sin A (-cos A/sin A)=-sin A + cosec A

x(-cos A)=(1/sin A)-sin A

x (-cos A)=(1-sin square)/sin A

x=(sin square A-1)/sin A cos A

:)