(i) Seg AB and seg AC of A ABC are the diameters of the circles
intersecting side BC in point D such that D divides side BC in
the ratio 3 : 1, then prove : ABP = AC? +
+ 1 / 2
BC
A
P
С
D
B
Answers
Answered by
0
- Seg AB and seg AC of A ABC are the
- diameters of the circles
Similar questions