Question

(i) Seg AB and seg AC of A ABC are the diameters of the circles
intersecting side BC in point D such that D divides side BC in
the ratio 3 : 1, then prove : ABP = AC? +
+ 1 / 2
BC
A
P
С
D
B​

Answer 1

1. Seg AB and seg AC of A ABC are the
2. diameters of the circles