Question

I sell a car at 10,000 $. If I had sold the car for 1,000 $ less, my profit percentage would reduce by 25%. How much did I buy the car for?

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Answer 1

Answer:

1000

Step-by-step explanation:

A dealer sold one car at a profit of 25% of the dealers purchase price for that car, let's say p1p1, for $20,000 --> p1∗1.25=20,000p1∗1.25=20,000 --> p1=16,000p1=16,000 --> profit=selling price−purchase price=20,000−16,000=4,000profit=selling price−purchase price=20,000−16,000=4,000;

A dealer sold another car at a loss of 20% of the dealers purchase price for that car, let's say p2p2, again for $20,000 --> p2∗0.8=20,000p2∗0.8=20,000 --> p2=25,000p2=25,000 --> loss=purchase price−selling price=25,000−20,000=5,000loss=purchase price−selling price=25,000−20,000=5,000;

Overall loss 5,000-4,000=1,000.

Or the way you are doing: the cars were purchased for p1+p2=16,000+25,000=41,000p1+p2=16,000+25,000=41,000, and sold for 20,000+20,000=40,00020,000+20,000=40,000 so the overall loss is 41,000−40,000=1,00041,000−40,000=1,000.

I think this is the answer

Answer 2

Answer:

Its easy to calculate the two amount of 41000 and 40000 but if you subtract 40000 from 41000 then you will have a profit of 1000 and vice- ...

Step-by-step explanation:

i hope this answer is useful for you bro