Question

i) simplify (3/7)⁶×(7/3)⁴×(1/7)-²
ii) simplify (2-¹÷5-⁵)²×(-5/8)-¹
iii) simplify [(2/3)²]³×(1/3)-⁴×3-¹×1/6
iv) simplify [(2/3)⁷]-⁵×(2/3)-³⁵
please help me​

Answer 1

i-in image

ii-don't know

$\small{iii - [\{(\frac{2}{3})^2\}^3\times (\frac{1}{3})^{-4}\times 3^{-1}\times (\frac{1}{6})]}$

$=[\{(\frac{4}{9})\}^3\times (3)^{4}\times\frac{1}{3} \times (\frac{1}{6})]$

$=[\frac{64}{729}\times 81\times\frac{1}{3} \times \frac{1}{6}]$

$=\frac{32}{81}$

$\therefore \: [\{(\frac{2}{3})^2\}^3\times (\frac{1}{3})^{-4}\times 3^{-1}\times (\frac{1}{6})]=\frac{32}{81}$

iv-don't know

Answer 2

hope this answer helps you