Question

(i) (sin 0 + cos 0) (sec 0 + cosec 0) = 2 + sec 0 cosec 0
the zeroes are thita ​

Answer 1

Step-by-step explanation:

(sin@+cos@)(1/cos@ +1/sin@)

= (sin@+cos@)(sin@+cos@)/sin@cos@)

=(sin@+cos@)^2*sec@cosec@

=(sin^2@+cos^2@+2sin@cos@)*sec@cosec@

=(1+2sin@cos@)*sec@cosec@

=sec@cosec@+2