(i) sin 25° cos 65° + cos 25° sin 65°
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Sin 25° cos 65° + cos25° sin 65°
Let 25° = A
65° = B
The given sum is the form
Sin A cosB + Cos A sin B
= Sin (A+B)
= Sin(25°+65°)
= Sin 90°
= 1
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Answered by
2
Answer:
Sin 25° cos 65° + cos25° sin 65°
Let 25°. = A
65° = B
It is in the form Sin A cos B + cos A sin B
= Sin(A+B)
= Sin(25°+65°)
= Sin 90°
= 1
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