Question

(i) sin 2x differentiation​

Answer 1

(i) 2sinxcosx

(ii) 2tanx/1+tan^2x

Answer 2

Answer:

2cos2X

Explanation:

Let y= sin 2x

Differentiating w.r.t x we get,

dy/dx = d(sin2x)/dx

= cos 2x.2 (since d(sinx)/dx = cosx)

= 2 cos 2x