Question

(i) sin (90° - A) sin A - cos (90° - A) cos A
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Answer 1

Answer:

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Answer 2

$\huge\underbrace\mathfrak\pink{ANSWER}$

cos(90−A)=sin(A);

sin(90−A)=cos(A);

tan(90−A)=cot(A)

cot(A)=

sin(A)

cos(A)

LHS

tan(90−A)

cos(90−A)sin(90−A)

=

cot(A)

sin(A)cos(A)

cot(A)

sin(A)cos(A)

=

cos(A)

sin(A)cos(A)sin(A)

cos(A)

sin(A)cos(A)sin(A)

=sin(A)sin(A)=sin

2

(A)=LHS

RHS=sin

2

(A)

LHS=RHS

Hence Proved