Question

i sin (A - A) - and abs(A+B) - then tind the value of R.​

Answer 1

ANSWER

We know that,

A×B=ABsinθ

Also,  A.B=ABcosθ

Given :  ∣A×B∣=3A.B

Using  ∣A×B∣=∣A∣∣B∣sinθ

We get  ∣A×B∣=ABsinθ

A.B=∣A∣∣B∣cosθ

∴  ABsinθ=3ABcosθ

tanθ=3⟹θ=60o

Now (A+B)2=A2+B2+2A.B

=A2+B2+2ABcosθ

=A2+B2+2AB×21

=A2+B2+AB

or ∣A+B∣=(A2+B2+AB)1/2

Answer 2

A +B = 1

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