Question

I
sin A+ cos A
6. If 4 cotA = 3, then find
sin A-COS A
('A' is acute)
​

Answer 1

Answer:

4cot A=3

cotA= 3/4

h²= 9+16=25

h==5

4/5- 3/5

hh=1/5

Answer 2

Step-by-step explanation:

Given:

$4 cot(A) = 3$

A is acute

To find:

$\sin(A) - \cos(A)$

Solution:

$4\cot(A) = 3 \: \: \ \: \: \: {(given})$

$= \cot(A) = \frac{3}{4}$

$= \frac{ \cos(A) }{ \sin(A) } = \frac{3}{4}$

therefore:

$\cos(A) = 3........mark \: as \: (1)$

$\sin(A) = 4.........mark \: as \: (2)$

now:

$\sin(A) - \cos(A)$

$= 4 - 3(from \: 1and2)$

$= 1$