Math, asked by sk0997611, 8 months ago

(i) sin A = cos B then proved that A+B = 90°.

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Answered by Anonymous
1

Answer:

Answer:Proved that A+B =90°

Answer:Proved that A+B =90°Step-by-step explanation:

Answer:Proved that A+B =90°Step-by-step explanation:It is given to us that Sin A =Cos B.

Answer:Proved that A+B =90°Step-by-step explanation:It is given to us that Sin A =Cos B.In that case, we have to prove that A+B =90°

Answer:Proved that A+B =90°Step-by-step explanation:It is given to us that Sin A =Cos B.In that case, we have to prove that A+B =90°Now, given expression, Sin A = Cos B

Answer:Proved that A+B =90°Step-by-step explanation:It is given to us that Sin A =Cos B.In that case, we have to prove that A+B =90°Now, given expression, Sin A = Cos B⇒ Sin A = Sin (90°-B)

Answer:Proved that A+B =90°Step-by-step explanation:It is given to us that Sin A =Cos B.In that case, we have to prove that A+B =90°Now, given expression, Sin A = Cos B⇒ Sin A = Sin (90°-B)Since, we know that Sin (n*90 - α) = Cos α, if n=1

Answer:Proved that A+B =90°Step-by-step explanation:It is given to us that Sin A =Cos B.In that case, we have to prove that A+B =90°Now, given expression, Sin A = Cos B⇒ Sin A = Sin (90°-B)Since, we know that Sin (n*90 - α) = Cos α, if n=1 =Sin α, if n=2

Answer:Proved that A+B =90°Step-by-step explanation:It is given to us that Sin A =Cos B.In that case, we have to prove that A+B =90°Now, given expression, Sin A = Cos B⇒ Sin A = Sin (90°-B)Since, we know that Sin (n*90 - α) = Cos α, if n=1 =Sin α, if n=2 = -Cos α, if n=3 and

Answer:Proved that A+B =90°Step-by-step explanation:It is given to us that Sin A =Cos B.In that case, we have to prove that A+B =90°Now, given expression, Sin A = Cos B⇒ Sin A = Sin (90°-B)Since, we know that Sin (n*90 - α) = Cos α, if n=1 =Sin α, if n=2 = -Cos α, if n=3 and = -Sin α, if n=4

Answer:Proved that A+B =90°Step-by-step explanation:It is given to us that Sin A =Cos B.In that case, we have to prove that A+B =90°Now, given expression, Sin A = Cos B⇒ Sin A = Sin (90°-B)Since, we know that Sin (n*90 - α) = Cos α, if n=1 =Sin α, if n=2 = -Cos α, if n=3 and = -Sin α, if n=4Hence, cancelling Sin from both sides, A= 90° - B, ⇒A+B = 90° (Proved)

Answered by itzJitesh
0

Answer:

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