Math, asked by smritakalita2004, 1 year ago

প্ৰমাণ কৰা যে (i)Sin45°=1/√2
(ii)Sin(90°-A)=Cos A
(জ্যামিতিব্দ ভাৱে)​

Answers

Answered by codiepienagoya
0

Given:

\bold{(i) \sin 45^{\circ} = \frac{1}{\sqrt{2}}}\\\\\bold{(ii) \sin(90^{\circ}-A) =  \cos A}

To find:

Prove.

Solution:

In the trigonometry (\sin (90^{\circ}- \theta)= \cos \theta \ \  that's  \ why  \  \ \sin (90^{\circ}- A)= \cos A ) and \sin 45^{\circ} = \frac{1}{\sqrt{2}} that's why both the given equation is true.

Answered by shivanisinha200725
1

Answer:

what a question???!?!?

Similar questions