Question

I solve : 5x2-22x-15=0​

Answer 1

Answer:

=−±2−4√2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

52−22−15=0

5x^{2}-22x-15=05x2−22x−15=0

=5

a={\color{#c92786}{5}}a=5

=−22

b={\color{#e8710a}{-22}}b=−22

=−15

c={\color{#129eaf}{-15}}c=−15

=−(−22)±(−22)2−4⋅5(−15)√2⋅5

x=\frac{-({\color{#e8710a}{-22}}) \pm \sqrt{({\color{#e8710a}{-22}})^{2}-4 \cdot {\color{#c92786}{5}}({\color{#129eaf}{-15}})}}{2 \cdot {\color{#c92786}{5}}}x=2⋅5−(−22)±(−22)2−4⋅5(−15)

2

Simplify

3

Separate the equations

Answer 2

Answer:

5x²-25x+3x-15=0

5x(x-5)+3(x-5)=0

(x-5)(5x+3)=0

(x-5)=0

x=5

(5x+3)=0

5x=-3

x=-⅗.