Question

I
solve
for x
&
y
12/x + 5/y = I
6o/X + 40/y =19​

Answer 1

follow me

Step-by-step explanation:

12y + 5x = xy

60y +40x = 19xy

then

60y + 25x = 5 xy

- 60y+ 40x =19xy

solve

then -15x= -19xy

x = 19/15

Answer 2

AnswEr

x = -36/11

y = 15/14

Given

The equations are :

• $\sf{ \frac{12}{x} + \frac{5}{y} = 1}$
• $\sf{\frac{60}{x} + \frac{40}{y} = 19}$

To Find

• The values of x and y

Solition

Let us consider 1/x = p and 1/y = q so that the equations becomes :

$\sf{12p + 5q = 1}\\ \implies \sf{60p+ 25q= 5 - - - (1)}$

And the another one

$\sf{60p+ 40q= 19 - - - (2)}$

Subtracting (1) from (2)

$\sf{60p + 40q - 60p - 25q = 19 - 5} \\ \sf {\implies15q = 14} \\ \implies \sf {q = \frac{14}{15} } \\ \implies \sf \frac{1}{y} = \frac{14}{15} \\ \implies \sf{y = \frac{15}{14} }$

And using the value of y in given equation we have :

$\sf \implies \frac{12}{x} + \frac{5}{ \frac{15}{14} } = 1 \\ \sf\implies \frac{12}{x} + \frac{70}{15} = 1 \\ \implies \sf \frac{12}{x} = 1 - \frac{14}{3} \\ \implies \sf{ \frac{12}{x} } = \frac{ - 11}{3} \\ \implies \sf{x = - \frac{36}{11} }$