I solve
i Which team of the sequence 2,5,8,11
is 128? if the sequence is an ap
Answers
Answered by
1
Answer:
n = 43
Step-by-step explanation:
an = a+(n-1)d
128 = 2 + (n-1) 3
128 = 2 + 3n - 3
3n = 129
n = 129/3
n = 43
Answered by
0
Answer:
43 rd term
Step-by-step explanation:
2a +( n-1 ) d = nth term
2×2 +( n-1 ) ×3 = 128
4 + 3n - 3 = 128
3n = 129
n= 43rd term .
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