Math, asked by purvesh58, 11 months ago

i)
Solve the following quadratic equation by factorisation:
4y2 - 11y =15​

Answers

Answered by samarthtripathi47
1

Answer:

(y+1)(4y-15)

Step-by-step explanation:

4y2-11y-15=0

4y2+4y-15y-15=0

4y(y+1) -15(y+1)

(y+1) (4y-15)

Answered by harendrachoubay
0

The value of  quadratic equation by factorisation of4y^{2} -11y-15=0 is (y-15)(y+1)=0.

Step-by-step explanation:

The given quadratic equation:

4y^{2} -11y-15=0

4y^{2} -15y+4y-15=0

y(y+1)-15(y+1)=0\\\\(y-15)(y+1)=0

The value of  quadratic equation by factorisation of4y^{2} -11y-15=0 is (y-15)(y+1)=0.

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