I st question is 3xy×(4x²+y) and second is-3p²q²(4P²q-3pq²+4P -5 q)
Answers
Answered by
0
Answer:
=(x-y)(4x+y+2)
Step-by-step explanation:
4x2−y2−3xy+2x−2y=(4x2−(4y2−3y2)−3xy+2x−2y)
=(4x2−4y2)+(3y2−3xy)+(2x−2y)=4(x2−y2)+3y(y−x)+2(x−y)
=4(x+y)(x−y)−3y(x−y)+2(x−y)=(x−y)(4(x+y)−3y+2)=(x−y)(4x+4y−3y+2)
=(x−y)(4x+y+2)
Similar questions