(i) State Newton’s three laws of motion. (ii) Find the value of the constant force that is applied for 1 second on a 10 kg object to increase the velocity of the object from 5 m/s to 10 m/s.
Answers
Explanation:
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Answer:
(i) Newton's 1st Law : A body remains at rest or in a constant speed along a straight line unless acted upon by an unbalanced external force
Newton's 2nd Law : The rate of change of momentum of an object is directly proportional to the applied force in the direction of force
Newton's 3rd Law : Every action has an equal and opposite reaction
(ii) F = m(v-u)/t
F = 10× (10-5)/1
F = 10 × 5
Thus F = 50N