I suck at math lmaoo
The function p(x) = –8x2 – 64x can be written in vertex form p(x) = a(x – h)2 + k, where a =__
,
h = __
, and k = __.
To graph the function p, reflect the graph of f(x) = x2 across the x-axis, vertically stretch the graph by a factor of 8, shift the graph __ units, and then shift the graph
__ units.
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Given : The function p(x) = –8x² – 64x can be written in vertex form
p(x) = a(x – h)² + k,
To Find : a , h and k
Solution:
p(x) = –8x² – 64x
=> p(x) = - 8 ( x² + 8x )
Add and subtract (8/2)² = 4² = 16 in bracket
so that ( x + y)² = x² + y² + 2xy identity can be applied
=> p(x) = - 8 ( x² + 8x + 16 - 16 )
=> p(x) = - 8 ( x² + 8x + 16) + 128
=> p(x) = - 8 ( x +4 )² + 128
=> p(x) = - 8 ( x - (-4) )² + 128
comparing with p(x) = a(x – h)² + k,
a = - 8
h = - 4
k = 128
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