Question

I/ Suman decides to give y4 times
social science study to maths,
calculate time for which he
studies maths!
B) 4/5 c) 57/10 d) 1/4​

Answer 1

Given:

Suman studies 4 times social science study to maths

To find:

time for which Suman studies maths T =?

Step-by-step explanation:

• Suppose Suman spent m time studying social science.
• Now, she decided to spend 4x times time on maths.
• The probability of her total study is 1.

         m + 4m = 1

         5 m = 1

         m = $\displaystyle\frac{1}{5}$

• So, the time spend by Suman to study maths subject is given by

         T = 4 m

            = 4 ×  $\displaystyle\frac{1}{5}$

         $\displaystyle \mathbf{T = \frac{4}{5} }$

Correct option is B.

Answer 2

Complete Question :- Suman planned her study in following manner.

• Science : 5/3 h
• Social Science :4/5 h
• Languages : 7/9 h
• Maths : 11/2 h.

( Based on this Answer the following. h means Hours)

1) how many improper fractions do you see above .

2) how long do Suman study in hours .

3) if Suman decides to give 1/4 times social science study to maths calculate time for which he studies maths.

4) what fraction of total study he do of languages .

Solution :-

we know that,

• when numerator is greater than denominator, the fraction is called as improper fraction .

so,

→ Science : 5/3 h = 5 > 3 = Improper fraction .

→ Social Science :4/5 h = 4 < 5 = Proper fraction .

→ Languages : 7/9 h = 7 < 9 = Proper fraction .

→ Maths : 11/2 h = 11 > 2 = Improper fraction .

therefore, total two improper fractions are there .

now,

→ Total time suman study in hours = (5/3) + (4/5) + (7/9) + (11/2) = (5*90+4*54+7*30+11*135)/270 = 2361/270 = (787/90) h .

now,

→ Suman total time for social Science = (4/5) h

and,

→ She gave time to study maths = (1/4) of (4/5) = (1/5) h

then,

→ Total time for which she study maths = (1/5) + (11/2) = (2 + 11*5)/10 = (57/10) h Option (c)

Now,

→ Fraction of total study he do of languages = (7/9) / (787/90) = (7/9) * (90/787) = (70/787)

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