i surely mark you as brainliest..pls solve these questions..
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Anonymous:
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1
That's the answer hope it helps you. GO BANKAI
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Because in parallel the voltage remains constant
why?
Its a rule
Remember in series current remain constant
and in parallel voltage remains constant
ok thank you bro
No probs
could you please solve other questions in my account.. nobody is answering..i want solutions, tomorrow is my exam..pls do you solve?
Ok will solve ad much as possible
tnq bro
Answered by
6
Hey mate here is your answer
.
C1,C2 and C3 are parallel
Ceff=C1+C2+C3
12=C1+C2+C3........eq1
C1C2C3=48.........eq2
C1 and C2 are in parallel
Ceff=C1+C2
C1C2=6.... ..eq3
from eq 1and 3
C3=6
Hence eq 3 becomes
C1C2=8....eq4
also from 2
C1=6-C2
(6-C2)C2=8
Cpower2 base2-6C2+8=0
from sloving it we get
C1=4
C2=2
C3=6
option is C
second question i dont know
mark as a brainlist
equation 4 i didn't understand
It is C1+C2=8
in eqn 3, C1+C2=6. but in eqn 4, C1+C2=8. how?
She has solved each capacitor value individually
Its correct
ignore my comment "c1+c2=8"
ok
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