Question

(i)
tan A + cot A = sec A cosec A​

Answer 1

Step-by-step explanation:

tan A + cot A

sinA/CosA+CosA/sinA

sin²A+cos²A/sinA.cosA

1/sinA.cosA

=sec A cosec A

Answer 2

Answer:

tan A + cot A

sinA/cosA + cosA/sinA

$\frac{ {sin}^{2}a \: \: \: + \: {cos}^{2} a }{sina \: cosa}$

1/ sina cosa

seca coseca