Question

i) tan o x tan (90 – 0) = ?

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Answer 1

Answer:

tan 0 * tan (90-0)= 1

Step-by-step explanation:

=Tan 0 * Tan (90-0)

= Tan 0 *Cot 0   {$\frac{opp}{adj}$ ×$\frac{adj}{opp}$}

= 1

Answer 2

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⇒ tanθ × tan(90 – θ) = 1

I.e

let θ = 60

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as we know that

★ cot θ = tan (90 – θ) ★

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⇒ tan θ × tan(90 – θ) = 1

⇒ tan 60 × tan(90 – θ) = 1

⇒ tan 60 × cot 30 = 1 ––– (1)

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as we know that .

★ cot θ = $\frac{1}{tan θ}$ ★

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⇒ tan 60 × cot 30 = 1 by –––(1)

⇒ $tan 60 × \frac{1}{tan60} = 1$

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tan 60 and tan 60 will get cancelled and remaining will be 1

so,

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LHS = RHS

1 = 1

hence proved .

$\huge\mathcal\color{lime}I\:hope\:it\:helps:you.$